However, when the wooden tray is touched, heat does not flow from our hands to the tray and we do not feel cold. i.e. 17. Hence, the CO2 vapour condenses to solid directly without going through the liquid phase. Equating equations (1) and (2), we get: ⇒\Rightarrow⇒ 45 °C – 20 °C = 25 °C above the room temperature and the body cools by 30 °C [ 60 °C – 30 °C ] within time t ( Assume ), Therefore, 30t\frac{30}{t}t30 = K × 25 . . 21. What is the fractional change in its density for a 30 °C rise in temperature? Chapter 2: Units And Measurements. . . Answer: (a) According to Kirchh off’s law of black body radiations, good emitters are good absorbers and bad emitters are bad absorbers. The length of a steel rod measured by this tape is found to be 63.0 cm on a hot day when the temperature is 45.0 °C. . Why ? A body with large reflectivity is a poor absorber of heat and consequently, it is also a poor emitter. 14.23 depicts four x-t plots for linear motion of a particle. (1), TF = (95)Tc\left( \frac{ 9 }{ 5 } \right ) T _{ c } (59)Tc + 32 . Using Newton’s law of cooling, the cooling rate is directly proportional to the difference in temperature. Physics is one of the core subjects for anyone who chooses to engineer. . Topics and Subtopics in NCERT Solutions for Class 12 Physics Chapter 11 Dual Nature of … Time taken to reduce the temperature, t = 20 min, Specific heat of the human body = Specific heat of water = c =1000 cal kg-1 0C-1 Some key points of Thermal Properties of Matter are given below. The ends of the rod are free to expand (Co-efficient of linear expansion of brass = 2.0 × 10–5 K–1, steel = 1.2 × 10–5 K–1 ). . Therefore, to raise the temperature of 1 mole of a diatomic gas through 1°C, heat is to be supplied to increase not only translational energy but also rotational and vibrational energies. 9. Co-efficient of linear expansion of brass = 2.0 x 10-5K-1; Young’s modulus of brass = 0.91 x 1011 Pa (1)Where the value of K is a constant. Therefore, the average rate of evaporation=86.2/20 8. A brass wire 1.8 m long at 27°C is held taut with little tension between two rigid supports. Question 11. (d) Is CO2 solid, liquid or gas at (a) – 70 °C under 1 atm (b) – 60 °C under 10 atm (c) 15°C under 56 atm? . So without the atmosphere, the earth would be inhospitably cold. (2), TF = (95)Tc+32\left( \frac{ 9 }{ 5 } \right ) T _{ c } + 32(59)Tc+32, = (95)×(−248.58)+32\left( \frac{ 9 }{ 5 } \right ) \times \left ( -248.58 \right ) + 32(59)×(−248.58)+32 = – 415.440F, = (95)×(−56.60)+32\left( \frac{ 9 }{ 5 } \right ) \times \left ( -56.60 \right ) + 32(59)×(−56.60)+32 = -69.880 F. Q.2: Two absolute scales A and B have triple points of water defined to be 200 A and 350 B. A cubical icebox of side 30 cm has a thickness of 5.0 cm. (a) At what temperature and pressure can the solid, liquid and vapour phases of CO2 co-exist in equilibrium ? Estimate the temperature of the part of the flame in contact with the boiler. (d) What is the temperature of the triple-point of water on an absolute scale whose unit interval size is equal to that of the Fahrenheit scale ? . Let m’ be the amount of water evaporated from the child’s body in 20 min. Final temperature of the metal block, T2 = 400C Q-11: The coefficient of volume expansion of glycerine is 49 × 10–5 K–1. NCERT Solutions For Class 12 Physics Chapter 11 Dual Nature of Radiation and Matter. . It is already known how important class 11th all about. According to approximate law. Which of the plots represent periodic … . Heat received by water: In the lesson' Mechanical Properties of Solids', you will … Thus, the above gases have significantly higher specific heats than monoatomic gasesChlorine has little larger specific heat as compared to the others in the list because it possesses vibrational motion as well while the rest only have rotational and translational motions. 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